Evaluation of Simple Formulas
Evaluation of Simple Formulas
To evaluate an algebraic expression means to
substitute given numbers for each literal symbol in the
expression and then carry out the indicated arithmetic to obtain
a single numerical value for the entire expression.
Example:
Evaluate 3x 2 5x + 7 for x = 2 and for x =
-5.
solution:
When x = 2, the expression becomes
3x 2 5x + 7 = 3(2) 2 5(2)
+ 7
= 3(4) 5(2) + 7
= 12 10 + 7
= 9
When x = -5, we get
3x 2 5x + 7 = 3(-5) 2
5(-5) + 7
= 3(25) 5(-5) + 7
= 75 + 25 + 7
= 107
Notice the use of brackets where convenient, particularly to
ensure the correct handling of negative numbers.
Example:
Evaluate when x = -3.
solution:
Substituting

We needed to take considerable care here to handle the
negative numbers correctly.
Example:
Evaluate when a = 2 and when a
= -2.
solution:
When a = 2, we get

When a = -2, we get

So, we get the same value for both a = +2 and for a = -2.
Although (3) 2 = 9 and (-3) 2 = 9, so that
both +3 and -3 are square roots of 9, the symbol stands for the positive
square root of 9 by definition. Thus, is always considered to
be +3.
Example:
Evaluate x 2 5x + 4 for x = 0, 1, 2, 3, 4,
and 5.
solution:
Here it is probably easiest to just make a table summarizing
our results:

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simplification of algebraic expressions (operations with polynomials (simplifying, degree, synthetic division...), exponential expressions, fractions and roots (radicals), absolute values) |
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finding LCM and GCF |
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operations with complex numbers (simplifying, rationalizing complex denominators...) |
 |
solving linear, quadratic and many other equations and inequalities (including basic logarithmic and exponential equations) |
 |
solving a system of two and three linear equations (including Cramer's rule) |
 |
graphing curves (lines, parabolas, hyperbolas, circles, ellipses, equation and inequality solutions) |
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graphing general functions |
 |
operations with functions (composition, inverse, range, domain...) |
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simplifying logarithms |
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