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Problema Solution

the distance necessary to stop a subway train at a given speed is inversely proportional to its deceleration. If a train is traveling at 30 mph requires 180 ft to stop when decelerating at 0.18g, what is the stopping distance at the same speed when it is stopping at 0.15g?

Answer provided by our tutors

Let

d = deceleration

s = the distance

x = the stopping distance that we need to find

The distance stopping at a given speed is inversely proportional to its deceleration means:

s*d = C, where C is constant

Now we use the given information:

180*0.18g = x*0.15g

0.15gx = 180*0.18g divide both sides by g

0.15x = 180*0.18

........

click here to see the equation solved for x

........

x = 216 ft

The stopping distance for a train traveling 30 mph with deceleration 0.15g is 215 feet.

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