Introduction
A system of equations is any group of equations.
A solution to a system of equations is a solution that works in every
equation in the group. For example, in the following system of equations:

the solution is x = 1, y = 2 because these values “work”
in both equations.
However, x = -3, y = 0 is not a solution for the system even though it is a
solution for the second equation.
Three methods of solving sytems of equations will be
discussed in this
supplement: the graphical method , substitution, and elimination.
The Graphical Method
The graphical method consists of graphing every equation
in the system and
then using the graph to find the coordinates of the point (s) where the graphs
intersect. The point of intersection is the solution.
Example 1. Use the graphical method to
solve the
following system of equations.

Solution: Carefully graph both equations
very precisely.
If you don’t graph neatly, your point of intersection
will be way off.
A graph is on the next page. The solution is x =
–1,
y = 1. Substitute these values into both equations to
check the solution.

Solution to Example 1.
Now You Try It #1. Use the graphical method
to solve.

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The graphical method also works if the equations are not
all linear.
| Example 2. Use the graphical method to
solve 
Solution: Carefully graph both equations
very precisely.
The graph below reveals two solutions : x = –1,
y = 1 and x = 2, y = 4. Check both solutions.

Now You Try It #2. Use the graphical method
to solve

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The graphical method is particularly helpful in
understanding why a system
of equations might have no solution.
| Example 3. Use the graphical method to
solve 
Solution: After carefully graphing the
equations, as
shown below, it becomes apparent the two lines are
parallel . Since parallel lines do not intersect, there
is no solution to this system of equation. A system
of equations that yields parallel lines is said to be
inconsistent: the lines are parallel, the equations are
inconsistent.

Now You Try It #3. Use the graphical method
to solve

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As easy as the graphical method is to use, it is not very
helpful when the
solution is not integers. Imagine trying to use the graphical method to find the
solution if the point of intersection is
Graphical Method Strengths: visualizing possible
solutions.
Graphical Method Weakness: imprecise.
The Substitution Method
To solve a system of equations using substitution, first
solve one of the
equations for a variable, then substitute it into the other equation(s). Always
substitute into the other equation(s) and always use parentheses.
Example 4. Use substitution to solve the
following sytem
of equations.

Solution. Step 1. Solve one of the
equations for a variable.
Let’s solve Eq. 1 for y.

Step 2. Substitute this into the other equation
(Eq. 2) and simplify.

Step 3. “Back-substitute” this value of x into the
equation from Step 1. to solve for y.

The solution is
You should put these
values into both original equations to check your
work.
Now You Try It #4. Use substitution to
solve

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If there is no solution to the system of equations
(parallel lines), the
substitution method will result in something nonsensical, such as 4 = –2. When
you are using the substitution method and end up with an equation that is false,
remember that it just means there is no solution.
One of the strengths of the substitution method is that it
works for systems
of equations that are difficult or impossible to graph. For example, the system

is not three lines, but rather is three planes. Each
equation is a different plane .
Solving requires finding the point where the three planes intersect. The diagram
below illustrates this.

Using substitution allows you to ignore the
three-dimensional or higher
dimensional aspects of the graphical interpretations of such equations.
Example 5. Use substitution to solve the
following system
of equations.

Solution: Step 1. Solve an equation for one
of the
variables. Let’s solve Eq. 1 for y.

Step 2. Substitute this value for y into BOTH of
the
OTHER equations. First into Eq. 2. When you
simplify, it becomes a simple equation with two
variables. (Use parentheses to keep the signs
straight) :

Do the same substituting into Eq. 3.

Step 3. Now use these two resulting equations

to solve for x and z. Using substitution all over
again on these two equation should give you x = 1,
z = 3.
Step 4. Now go back up to Step 1 and
back -substitute these values of x and z into the
equation for y.

The solution is x = 1, y = 2, z = 3. Use the
original
three equations to check this solution.
Now You Try It #5. Use substitution to
solve

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Elimination consists of adding equations together to
eliminate variables.
Sometimes you have to multiply equations by a number before you add them.
The goal is to end up with one equation that has just one variable. Then you can
use back-substitution to solve for the other variable(s).
When using elimination, eliminate one variable at a time.
It is also
important to write down “instructions” that indicate how you are manipulating
the
equations going from step to step.
| Example 6. Use elimination to solve

Solution Method1. Let’s get rid of the y
variable.
Multiplying the first equation by 5 and the second
equation by (–3) will make the y terms cancel

Now add the two new equations:

So x = –2. Use back-substitution to find that y =
1.
This works, but Method 2 below is a little quicker
and it generalizes to larger systems of equations
much more easily. Method 2 is what you’ll want to
use most of the time.
Solution Method 2. In this method, you
leave one
equation the same and replace the other equation(s).
Add 5 times the first equation to –3 times the
second equation. Put the result in for the second
equation.

Next multipy the second equation so x has a
coefficient of 1. Put it in for the second equation.

So x = –2. Once again, use back-substituion to
find
that y = 1. The solution is x = –2, y = 1.
Now You Try It #6. Use elimination to solve

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If there is no solution to the system of equations, the
elimination method
will yield a false statement, just like substitution does. The real power of the
elimination method becomes apparent in larger systems of equations.
Make sure you eliminate one variable at a time and be very
systematic.
Also, once you’ve got zeros in front of the variable you’re eliminating, avoid
doing anything later that will remove those zeros.
| Example 7. Use elimination to solve

Solution. First let’s knock out the y in
the second and third
equations.

Now we can multiply eq. 3 by 1/2 to give the z
term a
coefficient of 1. Coefficients of 1 are nice to work
with. Trying to make any other coefficient 1 would
introduce fractions , which is all right, but they can
be messy to work with.

Next add 3 times eq. 3 to eq. 2 and put it in for
eq. 2.

Equation 2 reveals x = 1. Back-substitute into eq.
3
to find z = 3. Back-substitute both x and z into eq. 1
to get y = 2. The solution is x = 1, y = 2, z = 3.
Now You Try It #7. Use elimination to solve

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This technique of elimination is used extensively in other
areas of
mathematics , including matrices and linear programming . Systematically and
neatly re-writing all the equations in each step is very important in preventing
errors and loosing big points on exams. It also is very important in the way
this
technique is generalized to other problems.
Exercises
In exercises 1-12, solve the systems of
equations graphically.

In exercises 13-24, solve the systems of
equations using substitution.. Don’t forget to
use parentheses.


In exercises 25-42, solve the systems of
equations using elimination. Be sure to write
out your work neatly with directions between
each step.


Solutions to Now You Try It.

Solutions to odd numbered exercises.


15. a = 2, b = 2 and a = -2, b = -2
17. no solution

21. x = 0, y = -3 and x = 3, y = 0
23. no solution
25. x = 2, y = -1
27. x = 2, y = 4
29. no solution
31. if x any number then

33. x = 2, y = 1 and x = -2, y = 1
35. x = 1, y = 0, z = 2
37. x = 0, y = 2, z = 1
39. no solution
41. x = 1, y = 2, z = 3, w = 4