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February 11th









February 11th

Linear Equations: Nature of Their Solutions

We show the structural similarities between the
linear algebraic equation and the linear differential
equation, and introduce the concept of
superposition of solutions for linear homogeneous
equations.

We then present the important nonhomogeneous
principle
, which gives the form of the
solutions for the general nonhomogeneous linear
equation, either algebraic or differential , as
the sum of the homogeneous solutions plus any
particular solution.

What is Linear?

An algebraic equation is
linear if it is of the form

where and C are constants. If
C = 0, the algebraic equation is said to be
homogeneous.

Example 1 Examine the fol lowing equations
to de termine which ones are linear

Example 2 The equation 5x + 4y - 3z = 4
is a linear equation that describes a plane in
3-space.
.
Example 3 A student has a monthly entertainment
budget of $50. The expected costs
are as follows: $8 for a movie ticket, $2 for
a video rental, $7 for a new paperback book
and $12 for a compact disc. This information
is represented by the linear equation

8m+2v +7b+12d = 50,

where m, v, b, and d represent the number of
movie
tickets, videos, books and CDs, respectively,
that the student can buy or rent in a
month if the entire budget is spent.

A differential equation
is linear if it is of the form



where all the functions of t are assumed to
be defined over some common interval I. If
f(t) = 0 over the interval I, the differential
equation is said to be homogeneous.

In particular, the general first- order linear differential
equation can be written as

y' +p(t)y = f(t).

The general second order linear differential equation
is

y'' +p(t)y' +q(t)y = f(t).

A differential equation that cannot be written
in the form required by the definition of linear
DE is a nonlinear differential equation.

Classifying Differential Equations

Several differential equations can be classified
according with the properties we ’ve just introduced

Equation Ord Lin/Nonlin Hom/Nonhom
linear
nonlinear
nonlinear
linear
nonlinear
linear
non-hom


hom

nonhom

Operator Notation

We introduce some simplifying notation, which
we will subsequently find very helpful.

We can write the linear algebraic equation (1)
simply as

L(x) = C,

where and the operator L
is defined as

Similarly, we can write the linear differential
equation (2) simply as

L(y) = f(t),

where and the operator
L is defined as

Linear Operator Property

We can easily confirm that the operators denoted
by L have the following properties, which
characterize linear operators:



Superposition Principle

Let and be any solution of the homogeneous
linear equation

L(u) = 0:

Then their sum is also a solution.
Furthermore a multiple is a solution
for any constant k.

Example 4

(a) The points (1, 3) and (2, 6) lie on the line
3x-y = 0. Check that their sum (1+2, 3+
6) = (3, 9) also lies on the same line.

(b) The points (2, 3, 5) and (-4,-5,-9) lie on
the plane x + y - z = 0. Check that their
sum (-2,-2,-4) also lies on the same plane.

(c) Two solutions of y'' - 4y = 0 are y = e2t
and y = e-2t. Check that y = e2t +e-2t is
also a solution.

Nonhomogeneous Principle

Let up be a particular solution to a linear nonhomogeneous
equation

L(u) = C (algebraic)

or

L(u) = f(t) (differential).

Then



is also a solution, where is a solution to the
associate homogeneous equation

L(u) = 0.

Furthermore, every solution of the nonhomogeneous
equation must be of the form .

Example 5 Consider the linear algebraic equation

x+y = 1.

The solutions of the associated homogeneous
equation x+y = 0 are Xh = c(1,-1), where c
is an arbitrary constant. A particular solution is
Xp = c(0, 1). Hence any solution is of the form
X = Xh+Xp = c(1,-1)+(0, 1) = (c, 1-c). Notice
that this is a line through the point (0, 1)
with direction given by the vector (1,-1).

Example 6 Consider the differential equation

1. Solve the associated homogeneous equation
y' - y = 0, to get

for any c ∈ IR.

2. Confirm, by differentiation and substitution
on (7), that



is a solution.

3. Form the sum and confirm that y = yh +
yp = cet - t - 1 is also a solution.

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