28.1 Introduction
In Grade 10, you studied graphs of many different forms . In this chapter, you
will learn a little
more about the graphs of exp onential functions .
28.2 Functions of the Form 
This form of the exponential function is slightly more complex than the form
studied in Grade
10.

Figure 28.1: General shape and position of the graph of a
function of the form
.
Activity :: Investigation : Functions of the Form

1. On the same set of axes, plot the fol lowing graphs :

Use your results to deduce the effect of a.
2. On the same set of axes, plot the following graphs:

Use your results to deduce the effect of q.
3. Following the general method of the above activities, choose your own values
of a and q to plot 5 different graphs of
to deduce the effect of
p.
You should have found that the value of a affects whether
the graph curves upwards (a > 0) or
curves downwards (a < 0).
You should have also found that the value of p affects the position of the
x-intercept.
You should have also found that the value of q affects the position of the
y-intercept.
These different properties are summarised in Table 28.1. The axes of symmetry
for each graph
is shown as a dashed line .
Table 28.1: Table summarising general shapes and positions of functions of the
form
.

28.2.1 Domain and Range
For
, the function is defined for all real
values of x. Therefore, the domain is
{x : x ∈ R}.
The range of
is dependent on the sign of a .
If a > 0 then:

Therefore, if a > 0, then the range is {f(x) : f(x) ∈
[q,∞)}.
If a < 0 then:

Therefore, if a < 0, then the range is {f(x) : f(x) ∈
(−∞,q]}.
For example, the domain of g(x) = 3 · 2x+1 + 2 is {x : x ∈ R}. For the range,

Therefore the range is {g(x) : g(x) ∈ [2,∞)}.

|
Exercise: Domain and Range
1. Give the domain of y = 3x.
2. What is the domain and range of f(x) = 2x ?
3. De termine the domain and range of y = (1,5)x+3. |
28.2.2 Intercepts
For functions of the form,
, the intercepts with the x and y axis
is calulated by
setting x = 0 for the y-intercept and by setting y = 0 for the x-intercept.
The y-intercept is calculated as follows :

For example, the y-intercept of g(x) = 3 · 2x+1 + 2 is
given by setting x = 0 to get:

The x-intercepts are calculated by setting y = 0 as
follows:

Which only has a real solution if either a < 0 or Q < 0.
Otherwise, the graph of the function of
form
does not have any x-intercepts.
For example, the x-intercept of g(x) = 3 · 2x+1 + 2 is given by setting x = 0 to
get:

which has no real solution. Therefore, the graph of g(x) =
3 · 2x+1 + 2 does not have any
x-intercepts.

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Exercise: Intercepts
1. Give the y-intercept of the graph of y = bx + 2.
2. Give the x- and y-intercepts of the graph of y = 1/2 (1,5)x+3 − 0,75. |
28.2.3 Asymptotes
There are two asymptotes for functions of the form
. They are
determined by
examining the domain and range.
We saw that the function was undefined at x = −p and for y = q. Therefore the
asymptotes
are x = −p and y = q.
For example, the domain of g(x) = 3 · 2x+1 + 2 is {x : x ∈ R, x
≠ −1} because g(x) is
undefined at x = −1. We also see that g(x) is undefined at y = 2. Therefore the
range is
{g(x) : g(x) ∈ (−∞,2) ∪ (2,∞)}.
From this we deduce that the asymptotes are at x = −1 and y = 2.
 |
Exercise: Asymptotes
1. Give the equation of the asymptote of the graph of y = 3x − 2.
2. What is the equation of the horizontal asymptote of the
graph of y = 3(0,8)x-1 − 3 ? |
28.2.4 Sketching Graphs of the Form

In order to sketch graphs of functions of the form,
, we need
to calculate
determine four characteristics:
1. domain and range
2. y-intercept
3. x-intercept
For example, sketch the graph of g(x) = 3 · 2x+1 + 2. Mark the intercepts.
We have determined the domain to be {x : x ∈ R} and the range to be {g(x) : g(x)
∈ [5,∞)}.
The y-intercept is
= 8 and there are no x-intercepts.

Figure 28.2: Graph of g(x) = 3 · 2x+1 + 2.

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Exercise: Sketching Graphs
1. Draw the graphs of the following on the same set of axes. Label the
horizontal
aymptotes and y-intercepts clearly.
Draw the graph of f(x) = 3x.
B Explain where a solution of 3x = 5 can be read off the graph.
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28.3 End of Chapter Exercises
1. The following table of values has columns giving the y-values for the graph y
= ax,
y = ax+1 and y = ax + 1. Match a graph to a column.

2. The graph of f(x) = 1 + a.2x (a is a constant) passes
through the origin.
A Determine the value of a.
B Determine the value of f(−15) correct to FIVE decimal places .
C Determine the value of x, if P(x; 0,5) lies on the graph of f.
D If the graph of f is shifted 2 units to the right to give the function h,
write down the
equation of h.
3. The graph of f(x) = a.bx (a ≠ 0) has the point
P(2;144) on f.
A If b = 0,75, calculate the value of a.
B Hence write down the equation of f.
C Determine, correct to TWO decimal places, the value of f(13).
D Describe the transformation of the curve of f to h if h(x) = f(−x).