FIRST: COUNT THE TERMS OF THE POLYNOMIAL ,
SECOND: FROM ALL THE TERMS, FACTOR OUT THE LARGEST
COMMON
FACTOR,
THIRD: DO YOU HAVE ONE OF THE FOL LOWING , BELOW:
If TWO Terms , do you have:
Difference of two Squares
a2 - b2 = (a - b)(a + b)
Sum of two Squares
a2 + b2 = a2 + b2 (NOT FACTORABLE in R!)
Difference of two Cubes
a3 – b3 = (a - b)(a2 + ab + b2)
Sum of two Cubes
a3 + b3 = (a + b)(a2 - ab + b2)
If THREE Terms, is it:
Perfect Square Trinomial (PST)
x2 + 2xy + y2 = (x + y) 2 ← square of a sum
x2 - 2xy + y2 = (x - y) 2 ← square of a difference
Any Trinomial (over for the product/ sum method )
ax2 + bx + c = ( _x + _y )( _x +_y )
If FOUR Terms, try:
Factoring by Grouping (into pairs)
xy - y + x2 - x (4 terms)
y(x - 1) + x(x - 1) (2 terms)
(x - 1 )(y + x) (1 term)
If MORE Terms:
Use long division for polynomials.
When the remainder is zero ,
then the divisor is a factor.
THE PRODUCT/SUM METHOD
for factoring any trinomial:
(1st coeff.) x2 + (middle coeff.) xy + (last coeff.) y2
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The METHOD:
1) Multiply the first and last coefficients of the
trinomial : (1st) • (last) = ab
2) Rewrite middle coefficient as a sum: (middle) = a + b
3) Find a and b to satisfy equations in #1 and #2. If you cannot find such a
and b
then the trinomial is not factorable .
4) Rewrite the middle term as two terms using a and b as their coefficients.
5) The trinomial can now be rewritten with 4 terms.
6) Factor the four terms by grouping. (The end!)
EXAMPLE 1: 9x2 - 6xy + 4y2 (in standard form)
1) Product of (1st) • (last) = (4) • (9) = 36, so ab =
36.
2) Middle term = -6, so a + b = -6
3) Find a and b that satisfy #1 and #2. There is no such a and b so the
trinomial is
not factorable. (The end!)
EXAMPLE 2: 9x2 - 12xy + 4y2 (in standard form)
1) Product of (1st) • (last) = (4) • (9) = 36, so ab = 36.
2) Middle term = -12, so a + b = -12.
3) Find a and b to satisfy #1 and #2: Here a = -6 and b = -6. (Check it!)
4) Rewrite the middle term using the a and the b found in #3: -12xy = -6xy +
-6xy
5) Rewrite the trinomial: 9x2 - 6xy - 6xy + 4y2 = (4 terms)
6) Factor by grouping:
3x(3x - 2y) - 2y(3x - 2y) = (2 terms)
(3x - 2y)(3x - 2y) = (1 term)
(3x - 2y) 2
The end!
(You may have noticed that Example 2 is a perfect square trinomial, a PST.)
OSU - N MATH LAB Prepared by Rose Hart