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Combining Like Terms
EXAMPLE SOLUTION Multiplying Expressions EXAMPLE SOLUTION §11.2
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| Definition | Example |
| Solving: In an equation containing a variable, finding which values of the variable make the equation a true statement. |
Is -7 a solution of : a + 23 = -16?
SOLUTION |
| Solution: In an equation, a value for the variable that makes the equation a true statement. |
Using the Addition Property to Solve Equations
| Distributive Property | |
| Let a, b, and c represent numbers. a = b and a + c = b + c are equivalent equations |
Then Also, a = b and a –c = b - c are equivalent equations |
EXAMPLE
Solve: f + 4 = -66
SOLUTION

Section Objectives
□ Using the Multiplication Property to Solve Equations
Using the Multiplication Property to Solve
Equations
| Multiplication Property of Equality | |
| Let a, b, and c represent numbers and c ≠ 0. Then | |
| a = b and a ∙ c = b ∙ c are equivalent equations |
Also, a = b and a/c = b/c are equivalent equations |
EXAMPLE
Solve: 7y = 21.
SOLUTION

Section Objectives
□ Solving Equations Using Addition and Multiplication
Properties
□ Solving Equations Containing Parentheses
□ Writing Sentences as Equations
Solving Equations Using Addition and
Multiplication Properties
EXAMPLE
Solve: 3y – 12 = 0.
SOLUTION

Solving Equations Containing Parentheses
| Steps | Example |
| Step 1: If parentheses are present,
use the distributive property. |
Solve: 3(x-1) = 12 |
| Step 2: Combine any like terms on
each side of the equation. |
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| Step 3: Use the addition property of
equality to rewrite the equation so that variable terms are on one side of the equation and constant terms are on the other side. |
|
| Step 4: Use the multiplication
property of equality to divide both sides by the numerical coefficient of the variable to solve for. |
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| Step 5: Check the solution in the
original equation. |
Writing Sentences as Equations
| Key Words or Phrases | Examples | Symbols |
| equals | 3 equals 2 plus 1 | 3 = 2 + 1 |
| gives | the quotient of 10 and -5 gives -2 | ![]() |
| is/was | 17 minus 12 is 5 | 17 –12 = 5 |
| yields | 11 plus 2 yields 13 | 11 + 2 = 13 |
| amounts to | twice -15 amounts to -30 | 2(-15) = -30 |
| is equal to | -24 is equal to 2 times -12 | -24 = 2(-12) |
Writing Sentences as Equations
EXAMPLE
Write the fol lowing sentence as an equation:
The product of -5 and -29 gives 145.
SOLUTION

Section Objectives
□ Writing Phrases as Algebraic Expressions
□ Writing Sentences as Equations
□ Using Problem-Solving Steps to Solve Problems
| Addition | Subtraction | Multiplication | Division | Equal Sign |
| sum | difference | product | quotient | equals |
| plus | minus | times | divided by | gives |
| added to | subtracted from | multiply | into | is/was |
| more than | less than | twice | per | yields |
| increased by | decreased by | of | amounts to | |
| total | less | double | is equal to |
Writing Phrases as Algebraic Expressions
EXAMPLE
Write the following phrase as a variable expression:
Ten plus a number
SOLUTION

Writing Sentences as Equations
EXAMPLE
Write the following sentence as an equation:
Five subtracted from a number equals 10.
SOLUTION

Using Problem-Solving Steps to Solve Problems
1. UNDERSTAND the
problem.
2. TRANSLATE THE PROBLEM INTO AN EQUATION.
3. SOLVE the equation.
4. INTERPRET the results.
EXAMPLE
The sum of 7, 9, and a number is 40. Find the number
UNDERSTAND
SOLUTION

The unknown number is 24.
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